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\\ \\ +Zn\rightarrow P+Q

 

What will be the P and Q?

Option: 1

and\ ZnBr_2 


Option: 2

H_2C=CH-CH_3\ and\ ZnBr_2


Option: 3

CH_3CH_2CH_3\ and\ ZnBr_2


Option: 4

and\ Br_2


Answers (1)

best_answer

This reaction is Frankland's reaction.

In this reaction, alkyl halides are treated with Zn to form alkane. In this case, since the substrate is a dibromide, intramolecular reaction will take place to form a cycloalkane.

+Zn\rightarrow +ZnBr_2

Therefore, option (1) is correct.

Posted by

Rakesh

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