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In a carnot engine, the temperature of reservoir is \mathrm{527^{\circ}C} and that of sink is \mathrm{200K}. If the worked by the engine when it tranfers heat from reservoir to sink is \mathrm{12000kJ}, the quantity of heat absorbed by the engine from reservoir is ________\mathrm{\times10^{6}J}.

Option: 1

16


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{Q_{1}=W+Q_{2}} \\

\mathrm{Q_{1}=12 \times 10^{6}+Q_{2} }\\             ........(1)

\mathrm{\frac{Q_{2}}{Q_{2}}=\frac{T_{2}}{T_{1}}=\frac{200}{800}=\frac{1}{4}} \\

\mathrm{Q_{2}=\frac{Q_{1}}{4}} \\                                ......(2)

Solving (1) and (2)

\mathrm{Q_{1}=16 \times 10^{6} \mathrm{~J}}

Hence the answer is \mathrm{16 \times 10^{6} \mathrm{~J}}

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