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  • In a CE transistor amplifier, the audio signal voltage across the collector resistance of<img alt="\mathrm{2\; k\Omega }" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B2%5C%3B%20

In a CE transistor amplifier, the audio signal voltage across the collector resistance of\mathrm{2\; k\Omega } is 2V. If the base resistance is \mathrm{1\; k\Omega }
and the current amplification of the transistor is 100, the input signal voltage is

Option: 1

0.1 V


Option: 2

1.0 V


Option: 3

1 mV


Option: 4

10 mV


Answers (1)

best_answer

The out voltage, across the load R_{C}

\mathrm{\mathrm{V}_0=\mathrm{I}_{\mathrm{C}} \mathrm{R}_{\mathrm{C}}=2}

The collector current \mathrm{(I_{C})}

\mathrm{\mathrm{I}_{\mathrm{C}}=\frac{2}{2 \times 10^3}=10^3 \mathrm{Amp}}

Current gain \mathrm{\beta }

\mathrm{(\beta) current\; gain =\frac{\mathrm{I}_{\mathrm{C}}}{\mathrm{I}_{\mathrm{B}}}=100 }

\mathrm{\mathrm{I}_{\mathrm{B}}=\frac{\mathrm{I}_{\mathrm{C}}}{100}=\frac{10^{-3}}{100}=10^{-5} \mathrm{Amp}}

Input voltage \mathrm{(V_{i})}

\mathrm{\begin{aligned} & V_i=R_B I_B=1 \times 10^3 \times 10^{-5}=10^{-2} \text { Volt } \\ & V_i=10 \mathrm{mV} \end{aligned}}

 

 

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