In a circuit for finding the resistance of a galvanometer by half deflection method, a 6 V battery and a high resistance of 11 kΩ are used. The figure of merit of the galvanometer is 60 μA/division. In the absence of shunt resistance, the galvanometer produces a deflection of θ=9 divisions when current flows in the circuit. The value of the shunt resistance that can cause the deflection of θ/2, is
closest to :

Answers (1)

As we have learned

Conversion of galvanometer into ammeter -

Connect a low resistance in parallel to the galvanometer

- wherein

 

 I=\frac{\varepsilon }{R+G}

G= 1/9\Omega

\frac{I}{2}= \frac{\varepsilon }{R+\frac{G*S}{G+S}}\times \frac{S}{S+G}\Rightarrow I/2= \frac{\varepsilon S}{R(S+G)+GS}

S=\frac{RG(I/2)}{\varepsilon -\frac{(RG)I}{2}}= \frac{11*10^{3}\times 1/9 *10^{3}*270*10^{-6}}{6-6/2}

S= 110\Omega

 

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