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In a common emitter circuit if VCC is changed by 0.2 V, collector current changes by \mathrm{4\times 10^{-3}}. The output resistance will be:

Option: 1

10 \mathrm{k} \Omega


Option: 2

30 \mathrm{k} \Omega


Option: 3

50 \mathrm{k} \Omega


Option: 4

70 \mathrm{k} \Omega


Answers (1)

best_answer

\mathrm{R=\frac{\Delta_{\text {knee }}}{\Delta l_{\text {ce }}}=\frac{0.2}{0.004 \times 10^{-3}}=50 \mathrm{~K} \Omega}

Posted by

shivangi.bhatnagar

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