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  • In a Davisson Germer experiment, the distance between two adjacent crystal planes is . What is the

In a Davisson Germer experiment, the distance between two adjacent crystal planes is 1.5 \AA . What is the angle of diffraction for constructive interference of electrons with a wavelength of 1.2 \AA?

Option: 1

31.7 degrees

 


Option: 2

48.6 degrees


Option: 3

24 degrees

 


Option: 4

61.4 degrees


Answers (1)

best_answer

The Davisson-Germer experiment involves the diffraction of electrons by a crystal. The condition for constructive interference is given by Bragg's law:

n \lambda=2 d \sin \theta

where n is an integer,\lambda is the wavelength of the electron, d is the distance between the crystal planes, and  \theta   is the angle of scattering.

Solving for \theta, we get:

\theta=\sin ^{-1}\left(\frac{n \lambda}{2 d}\right)

?Plugging in the values given in the question, we have:

\theta=\sin ^{-1}\left(\frac{2 \lambda}{d}\right)=\sin ^{-1}\left(\frac{1.22 \times 10^{-10} \mathrm{~m}}{2 \times 1.5 \times 10^{-10} \mathrm{~m}}\right)=\sin ^{-1}(0.4) \approx 24^{\circ}

 

Posted by

Shailly goel

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