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  • In a Fresnel's biprism experiment the distance between source and eyepiece is given 100 m and two slits are kept at a separation of 1.5 m. The observed fringe width is 0.5 mm. What will be the

In a Fresnel's biprism experiment the distance between source and eyepiece is given 100 m and two slits are kept at a separation of 1.5 m. The observed fringe width is 0.5 mm. What will be the wavelength of light?

Option: 1

1.5 \times 10^{-5} \mathrm{~m}


Option: 2

1.5 \times 10^{-6} m 


Option: 3

7.5 \times 10^{-6} m 


Option: 4

7.5 \times 10^{-5} \mathrm{~m}


Answers (1)

best_answer

As we learned

 

Fresnel's Biprism -

  • Fringes width has  value as  \beta=\frac{\lambda D}{d}

Given , 

D= 100 m

d= 1.5 m 

\beta = 0.5 mm 

use formula of fringe width \beta=\frac{\lambda D}{d}

Therefore,  \lambda =\frac{\beta d}{D}

Put the given values into the formula 

\lambda =\frac{0.5\times 10^{-3} \times 1.5}{100}

\lambda =7.5 \times 10^{-6}  m.

The correct option is 3.

Posted by

HARSH KANKARIA

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