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In a given transistor, the emitter current is changed by 2.1 mA. This results in a change of 2 mA in the collector current and a change of 1.05 V in the emitter-base voltage. The input resistance is:

Option: 1

\mathrm{5000\Omega }


Option: 2

\mathrm{3000\Omega}


Option: 3

\mathrm{1000 \Omega}


Option: 4

\mathrm{500\Omega}


Answers (1)

best_answer

\mathrm{\text { Input resistance }=\frac{\Delta \mathrm{V}_{\mathrm{EB}}}{\Delta \mathrm{I}}=\frac{1.05}{2.1 \times 10^{-3}}=500 \Omega}

Posted by

Pankaj Sanodiya

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