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  • In a L-R circuit applied voltage,  then current would be ( <img alt="

In a L-R circuit applied voltage, V=V_{0}Sin\omega t, then current would be ( \Phi is phase b/w voltage & current)

Option: 1

i=i_{o}Sin\omega t


Option: 2

i=i_{o}Sin(wt+\phi)


Option: 3

i=i_{o}Sin(wt-\phi)


Option: 4

i=i_{o}Sin(wt-\frac{\phi}{2})


Answers (1)

As we learned

Current -

{i}'= {i}'_{0}\sin \left ( \omega t-\phi \right )

-

 

 In a L-R circuit

Applied leads current by \phi phase in L-R circut.

Posted by

Ramraj Saini

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