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  • In a purely inductive circuit, if frequency is halved then what happens to current and inductive

In a purely inductive circuit, if frequency is halved then what happens to current and inductive reactance? 

 

Option: 1

Inductive reactance will be doubled and current will be half. 

 


Option: 2

Inductive reactance and current, both get halved.

 


Option: 3

Inductive reactance and Current, both get doubled.

 


Option: 4

Inductive reactance will be halved and current will be doubled.

 


Answers (1)

best_answer

\text { Initially let frequency is } \omega \text {. }

then\ \chi_L=\omega\ L\\ \\and\ I=\frac{V}{X_L}=\frac{V}{\omega L}                   -(1)

\\If\ frequency\ get\ half\ ie\ \frac{\omega}{2}. \\X_L^{\prime}=\frac{\omega L}{2} .

\text { And } I^{\prime}=\frac{V}{X_L^{\prime}}=\frac{V}{\omega L}=\frac{2 V}{\omega L}

\left.I^{\prime}=2 I \text { [using eq. } 1\right]

Posted by

himanshu.meshram

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