Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In a second-order reaction. How does the rate change when the concentration of a reactant is doubled?Option: 1 The rate remains unchanged<b

In a second-order reaction. How does the rate change when the concentration of a reactant is doubled?

Option: 1

The rate remains unchanged


Option: 2

The rate doubles


Option: 3

The rate quadruples.


Option: 4

The rate decreases by half.


Answers (1)

best_answer

In a second -order reaction. the rate is directly proportional to the square of the reactant concentration. When the concentration is doubled, the rate increase by a factor of four.

\mathrm{R=k(A)^{2}}

\mathrm{A \rightarrow 2 A}
\mathrm{R^{\prime}=k[2A]^{2}=4 k[A]^{2}=4 R}
\mathrm{R^{\prime}=4 R}

Posted by

Ritika Kankaria

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main Maths 2025: Five tips to score high marks in ‘toughest’ subject; most important chapters
anam-khan

JEE Main 2025 exam city intimation slip for session 1 soon at jeemain.nta.nic.in
anam-khan

Focus on modern physics, formulas to solve tricky problems; 5 tips to tackle JEE Main physics 2025

Latest Question