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  • In a semiconductor, the number density of intrinsic charge carriers at   is <img alt="1.5 \times 10^{16} / \mathrm{m}^{3}" sr

In a semiconductor, the number density of intrinsic charge carriers at 27^{\circ} \mathrm{C}  is 1.5 \times 10^{16} / \mathrm{m}^{3}. If the semiconductor is doped with impurity atom, the hole density increases to 4.5 \times 10^{22} / \mathrm{m}^{3}. The electron density in the doped semiconductor is ________\times 10^{9} / \mathrm{m}^{3}.
 

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best_answer

n_{i}= 1\cdot 5\times 10^{16}/m^{3}
n_{h}= 4\cdot 5\times 10^{22}/m^{3}
n_{e}= ?
We know that,
Intrinsic change carrier density= ni = \sqrt{n_{h}n_{e}}
n_{i}= \sqrt{n_{h}n_{e}}
1\cdot 5\times 10^{16}= \sqrt{4\cdot 5\times 10^{22}\times n_{e}}
2\cdot 25\times 10^{32}=4\cdot 5\times 10^{22}\times n_{e}
                  n_{e}= 0\cdot 5\times 10^{10}
                  n_{e}= 5\times 10^{9}\: m^{-3}

Posted by

vishal kumar

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