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  • In a statistics class, the mean and standard deviation of the scores obtained by students on a test were found to be 57 and 12 , respectively. If the scores are normally distributed, what percentag

In a statistics class, the mean and standard deviation of the scores obtained by students on a test were found to be 57 and 12 , respectively. If the scores are normally distributed, what percentage of students scored below 60 ?

Option: 1

\quad 66.36 \%


Option: 2

56.48 \%


Option: 3

96.52 \%


Option: 4

59.87 \%


Answers (1)

best_answer

To determine the percentage of students who scored below 60 , we can use the properties of the normal distribution.

First, we need to calculate the Z-score for a score of 60 . The Z-score represents the number of standard deviations a particular value is from the mean.

The formula to calculate the Z-score is:

\mathrm{ Z=(X-\mu) / \sigma }

Where:

\mathrm{ \begin{aligned} Z & =Z \text {-score } \\ X & =\text { Score } \\ \mu & =\text { Mean } \\ \sigma & =\text { Standard deviation } \end{aligned} }

Plugging in the values:

\mathrm{ \begin{aligned} & Z=(60-57) / 12 \\ & Z=3 / 12 \\ & Z=0.25 \end{aligned} }

Next, we need to find the cumulative probability associated with the Z-score of 0.25 . This represents the percentage of values below 60 .

Using a standard normal distribution table or a calculator, we can find that the cumulative probability associated with a Z-score of 0.25 is approximately 0.5987 .

To convert this probability to a percentage, we multiply it by 100 :

\mathrm{ \begin{aligned} \text { Percentage } & =0.5987 \times 100 \\ \text { Percentage } & \approx 59.87 \% \end{aligned} }
Therefore, approximately 59.87 \% of students scored below 60 on the test.

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Shailly goel

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