Get Answers to all your Questions

header-bg qa

In a transistor if collector current is 25 \mathrm{~mA} and base current is 1 \mathrm{~mA}, then current amplification factor \mathrm{\alpha} is

Option: 1

\frac{25}{24}


Option: 2

\frac{24}{25}


Option: 3

\frac{25}{26}


Option: 4

\frac{26}{25}


Answers (1)

best_answer

Here,
Collector current, \mathrm{I_C=25 \mathrm{~mA} }
Base current, \mathrm{I_B=1 \mathrm{~mA} }
As \mathrm{ I_E=I_B+I_C=(1+25) m A=26 m A }
As \mathrm{\alpha=\frac{I_C}{I_E}=\frac{25 \mathrm{~mA}}{26 \mathrm{~mA}}=\frac{25}{26} }

Posted by

manish

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE