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In a vernier callipers, each \mathrm{cm} on the main scale is divided into 20 equal parts. If tenth vernier scale division coincides with nineth main scale division. Then the value of vernier contant will be_________ \times 10^{-2} \mathrm{~mm}.

Option: 1

5


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{1\, MSD= \frac{1cm}{20}= 0.05\, cm}
\mathrm{10\, VSD= 9\, MSD}
\mathrm{Vernier\, constant= Least\, counct= 1MSD-1\, VSD}
                                                                     \mathrm{= 0.1\, MSD}

   \mathrm{Vernier\, constant=5\times 10^{-3}\, cm}
                                       \mathrm{=5\times 10^{-2}\, mm} 

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manish

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