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In a vertical plane other than magnetic meridian the angle of dip is 30^{o}. If this plane is rotated by 90^{o} keeping it vertical then angle of dip becomes 45^{o}. The true dip at that place is

Option: 1

\tan ^{-1}\left ( 2 \right )


Option: 2

\cot ^{-1}\left ( 3 \right )


Option: 3

\cot ^{-1}\left ( \frac{1}{3} \right )

 


Option: 4

\tan ^{-1}\left ( \frac{1}{2} \right )


Answers (1)

best_answer

Answer (4)

\tan 30^{o}=\frac{Bv}{B_{h}\cos \phi }

\tan 45^{o}=\frac{Bv}{B_{h}\sin \phi }

Posted by

Divya Prakash Singh

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