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In an examination, there are 5 multiple choice questions with 3 choices, out of which exactly one is correct. There are 3 marks for each correct answer, -2 marks for each wrong answer and 0 mark if the question is not attempted. Then, the number of ways a student appearing in the examination gets 5 marks is_________.

Option: 1

40


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\mathrm{x_{1}+x_{2}+x_{3}+x_{4}+x_{5}= 5}

\mathrm{x_{i}= 3\; or\; -2\; or\; 0}

Possible only when  3,3,3,-2,-2

\mathrm{Total\; ways\; = \frac{5!}{3!\, 2!} \times 2\times 2=40 }

(2 x 2 as there are two wrong options for each of the question marked incorrectly) 

Posted by

Shailly goel

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