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In an experiment, a transparent material is placed on a flat glass plate. A traveling microscope is used to measure the apparent shift in the position of an object placed beneath the glass plate when viewed from the top. The actual shift is d=5 \mathrm{~cm}, and the length of the microscope tube is L=25 \mathrm{~cm}. The least count of the traveling microscope is L C=0.01 \mathrm{~mm}.

The refractive index n of the transparent material is:

Option: 1

1.2


Option: 2

1.22


Option: 3

1.3


Option: 4

1.8


Answers (1)

best_answer

The refractive index n of the transparent material can be calculated using the formula: 

n=1+\frac{d}{L}

Given:

\begin{aligned} & d=0.5 \mathrm{~mm}=0.05 \mathrm{~m} \\ & L=25 \mathrm{~cm}=0.25 \mathrm{~m} \end{aligned}

Substitute the values into the formula:

n=1+\frac{0.05 \mathrm{~m}}{0.25 \mathrm{~m}}=1+0.2=1.2

\mathrm{n}=1.2

Posted by

Gautam harsolia

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