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  • In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf 1.5 V is found to be 60 cm. If this cell is replaced by another cell of emf E, the leng

In an experiment to find emf of a cell using potentiometer, the length of null point for a cell of emf
1.5 V is found to be 60 cm. If this cell is replaced by another cell of emf E, the length-of null point  increases by 40 cm. The value of E is   \frac{x}{10}V . The value of x is ________.

Option: 1

25


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{E}_1=\mathrm{K} \ell_1 \\ & \mathrm{E}_2=\mathrm{K} \ell_2 \\ & \therefore \frac{\mathrm{E}_2}{\mathrm{E}_1}=\frac{\ell_2}{\ell_1} \\ & \frac{\mathrm{E}}{1.5}=\frac{100}{60} \\ & \therefore \mathrm{E}=1.5 \times \frac{10}{6} \end{aligned}

\begin{aligned} & =\frac{3}{2} \times \frac{10}{6} \\ & =\frac{5}{2} \\ & =2.5 \\ & =\frac{25}{10} \\ & \therefore x=25 \end{aligned}

 

Posted by

Suraj Bhandari

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