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In an experiment with vernier calipers of least count 0.1 mm, when two jaws are joined together the zero of vernier scale lies right to the zero of the main scale and 6th division of vernier scale coincides with the main scale division. While measuring the diameter of a spherical bob, the zero of vernier scale lies in between 3.2 cm and 3.3 cm marks, and 4th division of vernier scale coincides with the main scale division. The diameter of bob
is measured as 

Option: 1

3.25 cm


Option: 2

3.22 cm


Option: 3

3.18 cm


Option: 4

3.26 cm


Answers (1)

best_answer

The zero error in verniel scale is = 6 × 0.1mm = 0.6 mm (+ve zero error)

Note: +ve zero error will have to be subtracted From the reading of the object.

Now, the diameter measured with the help of Vernier scale is

\begin{aligned} \text { Given by } & \rightarrow \text { M.S.D + V.S.D } \times \text { L.S } \\ & \Rightarrow 3.2 \mathrm{~cm}+0.1 \mathrm{~mm} \times 4 \\ & =3.24 \mathrm{~cm} \end{aligned}

\text { The actual diameter is } \Rightarrow 3.24 \mathrm{~mm} \text { - (zero error) }=3.24-0.6=3.18 \mathrm{~cm}

Posted by

Ritika Jonwal

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