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In an L-R circuit , the value of L is \left ( \frac{0.4}{\pi } \right ) henry and the value of R is 30 ohm.If in the circuit , an alternating emf of 200 volt at 50 cycles per second is connected, the impedance of the circuit and current will be ;

Option: 1

11.4 ohm, 17.5 ampere


Option: 2

30.7 ohm, 6.5 ampere


Option: 3

40.4 ohm, 5 ampere


Option: 4

50 ohm, 4 ampere.


Answers (1)

best_answer

Here,

\mathrm{\begin{aligned} & X_L=\omega L=2 \pi \mathrm{L} \\ & =2 \pi \times 50 \times \frac{0.4}{\pi}=40 \Omega \\ & \mathrm{R}=30 \Omega \\ & \mathrm{Z}=\sqrt{\mathrm{R}^2+\mathrm{X}_{\mathrm{L}}^2}=\sqrt{30^2+40^2}=50 \Omega \\ & \mathrm{I}_{\mathrm{m}}=\frac{\mathrm{V}_{\mathrm{m}}}{\mathrm{Z}}=\frac{200}{50}=4 \mathrm{~A} \end{aligned}}

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Rakesh

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