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  • In an LCR circuit ohm. When capacitance C is removed, the current lags behind the voltage by

In an LCR circuit \mathrm{R=100}ohm. When capacitance C is removed, the current lags behind the voltage by \pi / 3 . When inductance L is removed, the current leads the voltage by \pi / 3. The impedance of the circuit is

Option: 1

50 ohm


Option: 2

100 ohm


Option: 3

200 ohm


Option: 4

400 ohm


Answers (1)

best_answer

\mathrm{\text { When } C \text { is removed circuit becomes } R L \text { circuit hence } \tan \frac{\pi}{3}=\frac{X_L}{R}}               ...[i]

\mathrm{\text { When } L \text { is removed circuit becomes } R C \text { circuit hence } \tan \frac{\pi}{3}=\frac{X_c}{R}}                ...[ii]

\mathrm{\text { From equation (i) and (ii) we obtain } X_L=X_C \text {. This is the condition of resonance and in resonance }}

\mathrm{Z=R=100 \Omega \text {. }}

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Nehul

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