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In an n-p-n common emitter (CE) transistor the collector current changes from 5 \mathrm{~mA} to 16 \mathrm{~mA}for the change in base current from 100 \mu \mathrm{A}  and  200 \mu \mathrm{A}, respectively. The current gain of transistor is ________.

Option: 1

110


Option: 2

9


Option: 3

0.9


Option: 4

210


Answers (1)

best_answer

\beta=\frac{\Delta \mathrm{I}_{\mathrm{C}}}{\Delta \mathrm{I}_{\mathrm{B}}} \, \, \, \, \, \, \quad \Delta \mathrm{I}_{\mathrm{C}}=16-5=11 \mathrm{~mA}, \Delta \mathrm{I}_{\mathrm{B}}=200-100=100 \mu \mathrm{A}

\begin{aligned} & \beta=\frac{11 \times 10^{-3}}{100 \times 10^{-6}} \\ & \beta=\frac{11000}{100} \\ & \beta=110 \end{aligned}

Posted by

HARSH KANKARIA

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