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In an n-p-n transistor circuit, the collector current is 10 mA. If 90% of the electrons emitted reach the collector :

Option: 1

the emitter current will be 9 mA
 


Option: 2

the emitter current will be 10 mA
 


Option: 3

the base current will be 1 mA
 


Option: 4

the base current will be –1 mA


Answers (1)

best_answer

Given : 

\mathrm{\mathrm{I}_{\mathrm{c}}=10 \mathrm{~mA}=(0.9) \mathrm{i}}

\mathrm{\text { [Given that ic is } 90 \% \text { of le] }}

\mathrm{\begin{array}{ll} \therefore & \mathrm{i}_e=\frac{10}{0.9} \mathrm{~mA} \approx 11 \mathrm{~mA} \\ \text { and } & \mathrm{i}_b=\mathrm{i}_e-\mathrm{i}_c(11-10) \mathrm{mA}=1 \mathrm{~mA} \end{array}}

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rishi.raj

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