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In an optical fibre transmission, if the intensity of light becomes half of the light intensity at source (origin), Then the attenuation will be : 

Option: 1

0.30 dB


Option: 2

3.01 dB 


Option: 3

0.60 dB


Option: 4

6.02 dB 


Answers (1)

best_answer

As we have learned

Attenuation (in dB) -

Attenuation = 10\log_{10}\left ( I/I_{0} \right )

 

- wherein

[ in dB] I_{0}\: and \: I are initial and final intensity

 

 Attenuation in an optical fibre transmission is given by 10 log _{10}\left ( \frac{I_0}{I} \right )dB

Here given that I = I_0/2

Thus attenuation = 10 log _{10}\left ( \frac{I_0}{I} \right )dB

                                 10 log _{10}\left ( \frac{I_0}{I_0/2} \right )dB

                                 = 10\: \: log _{10}2\: \: dB

Attenuation = 3.01 dB 

 

 

 

 

 

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