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  • In finding the electric field using Gauss law the formula <img alt="\left | \vec{E} \right |=\frac{q_{enc}}{\epsilon _{0}\left | A \right |}" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cleft%20%7C%20%5Cvec%7BE%7D%20%5Cright%20%7C%3D%5C

In finding the electric field using Gauss law the formula \left | \vec{E} \right |=\frac{q_{enc}}{\epsilon _{0}\left | A \right |}  is applicable. In the formula \epsilon _{0} is permittivity of free space, A is the area of Gaussian surface and q _{enc} is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation? 
Option: 1 For any choice of Gaussian surface.
Option: 2 Only when the Gaussian is an equipotential surface.
Option: 3 Only when Gaussian surface is an equipotential surface and \left | \vec{E} \right | is constant on the surface.
Option: 4 Only when \left | \vec{E} \right | = constant on the surface. 

Answers (1)

best_answer

As Gauss's law is one of the fundamental laws of physics which states that the net flux of an electric field in a closed surface is directly proportional to the enclosed electric charge.  

And

The relation of gauss's law is valid when

The magnitude of the electric field is constant & the surface is equipotential

So the correct option is 3.

Posted by

vishal kumar

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