# In finding the electric field using Gauss law the formula $\left | \vec{E} \right |=\frac{q_{enc}}{\epsilon _{0}\left | A \right |}$  is applicable. In the formula $\epsilon _{0}$ is permittivity of free space, A is the area of Gaussian surface and $q _{enc}$ is charge enclosed by the Gaussian surface. This equation can be used in which of the following situation?  Option: 1 For any choice of Gaussian surface. Option: 2 Only when the Gaussian is an equipotential surface. Option: 3 Only when Gaussian surface is an equipotential surface and  is constant on the surface. Option: 4 Only when  = constant on the surface.

As Gauss's law is one of the fundamental laws of physics which states that the net flux of an electric field in a closed surface is directly proportional to the enclosed electric charge.

And

The relation of gauss's law is valid when

The magnitude of the electric field is constant & the surface is equipotential

So the correct option is 3.

## Most Viewed Questions

### Preparation Products

##### Knockout JEE Main (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-
##### Knockout JEE Main (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-
##### Test Series JEE Main 2024

Chapter/Subject/Full Mock Tests for JEE Main, Personalized Performance Report, Weakness Sheet, Complete Answer Key,.

₹ 7999/- ₹ 4999/-
##### JEE Main Rank Booster 2023

Booster and Kadha Video Lectures, Unlimited Full Mock Test, Adaptive Time Table, Faculty Support.

₹ 9999/- ₹ 6999/-
##### Knockout JEE Main (One Month Subscription)

Personalized AI Tutor and Adaptive Time Table, Self Study Material, Unlimited Mock Tests and Personalized Analysis Reports, Faculty Support.

₹ 7999/- ₹ 4999/-
Boost your Preparation for JEE Main 2021 with Personlized Coaching

Exams
Articles
Questions