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  • In Freundlich adsorption isotherm, slope of AB line is: Option: 1 n with (n, 0.1 to 0.5) Option: 2

In Freundlich adsorption isotherm, slope of AB line is:
Option: 1 n with (n, 0.1 to 0.5)
Option: 2 \frac{1}{n} with \left (\frac{1}{n} = 0 to 1 \right )
Option: 3 \log \frac{1}{n} with (n<1)
Option: 4 \log n \text{with }(n>1)

Answers (1)

best_answer

We know,

\\\mathrm{\frac{x}{m}=k\left ( P \right )^{1/n}} \\\\ \mathrm{log\frac{x}{m}=logk+log\left ( P \right )^{1/n}= logk+\frac{1}{n}log\left ( P \right ) } \\

The equation of a line is

y = mx+c , where m= slope.

After comparing the equation,

Slope m = 1/n.

So, the slope of AB line is 1/n. 

Posted by

sudhir.kumar

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