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  • . In given reaction, half -life period is directly proportiona

\mathrm{6 A \rightarrow P}. In given reaction, half -life period is directly proportional to initial conc of reactant. The initial rate of reaction is \mathrm{800 \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~min}^{-1}}.Calculate the half life period (in min) when initial conc.  of reactant is \mathrm{400 \mathrm{~mol} \mathrm{~L}^{-1} }.

Option: 1

\frac{1}{20}


Option: 2

\frac{1}{24}


Option: 3

\frac{1}{12}


Option: 4

24


Answers (1)

best_answer

(second -order reaction)

\mathrm{ t_{1 / 2}=\frac{[A]_{0}}{2 K_{A}}=\frac{[A]_{0}}{2 \times 6 K}=\frac{400}{2 \times 6 \times 800}=\frac{1}{24} \mathrm{~min}}

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Sayak

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