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  • In how many ways   tickets can be divided into <img alt="2" src="https://entrancecorner.oncodecogs.com/gif.la

In how many ways 20  tickets can be divided into 2 groups such that all contain 10 tickets to each.

Option: 1

92300


Option: 2

18300


Option: 3

18356


Option: 4

92378


Answers (1)

best_answer

The given information is:

Number of tickets =20

Number of teams =2

Number of tickets to each group =10

Pick first 10 tickets from 20 tickets, 

Total no. of ways of choosing is:

\frac{20 !}{(20-10) ! 10 !}=\frac{20 !}{10 ! 10 !}=184756

Pick last 10 tickets from 10 tickets are and the number of ways this can be done is 1 .

Since the two groups are similar, there is no differentiation between them. Therefore, we need to divide it with 2 !=2 .

The total numbers of ways:

\frac{184756}{2}=92378

Posted by

Suraj Bhandari

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