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In qualitative analysis, in order to detect second group basic radical, \mathrm{H}_{2} \mathrm{S} gas is passed in the presence of dilute HCl to

Option: 1

Increase in dissociation of \mathrm{H}_{2} \mathrm{S}


Option: 2

Decrease the dissociation of salt solution


Option: 3

Decrease the dissociation of \mathrm{H}_{2} \mathrm{S}


Option: 4

Increase the dissociation of salt solution


Answers (1)

best_answer

\mathrm{HCl} being a strong acid suppresses ionisation of the weak acid \mathrm{H}_{2} \mathrm{S}. This results in a lesser \mathrm{[S^{2-}]} which is sufficient to cause the precipitation of the sulphides of Group II radicals exceed their corresponding solubility product and hence only these are precipitated.

Hence, the correct answer is Option (3)

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Gaurav

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