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# In the angle of friction how Meu =tantheta comes ??

Meu = tank theta please explain this

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Here we have the FBD of the block on the wedge.

By the figure,

$\frac{\mu mg\cos \Theta }{mg\cos \Theta} = \frac{mg\sin \Theta}{mg\cos \Theta}$

$\Rightarrow \mu = \tan \Theta$

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