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In the Bohr model of a hydrogen atom, the centripetal force is furnished by the coulomb attraction between the proton and the electron. If a_{0} is the radius of the ground state orbit, m is the mass, e is the charge on the electron and \varepsilon _{0} is the vacuum permittivity, the speed of the electron is

Option: 1

0


Option: 2

\frac{e}{\sqrt{\varepsilon_0 a_0 m}}


Option: 3

\frac{e}{\sqrt{4 \pi \varepsilon_0 a_0 m}}


Option: 4

\frac{\sqrt{4 \pi \varepsilon_0 a_0 m}}{e}


Answers (1)

best_answer

\frac{m v^2}{a_0}=\frac{1}{4 \pi \varepsilon_0} \frac{e^2}{a_0^2} \Rightarrow v=\frac{e}{\sqrt{4 \pi \varepsilon_0 a_0 m}}

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