Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • In the case of a common emitter transistor amplifier the ratio of the collector current to the emitter current <img alt="\mathrm{\frac{I_{c}}{I_{e}}}" src="https://entrancecorner.oncodecogs.co

In the case of a common emitter transistor amplifier the ratio of the collector current to the emitter current \mathrm{\frac{I_{c}}{I_{e}}} is \mathrm{0.96}. The current gain of the amplifier is

Option: 1

6


Option: 2

48


Option: 3

24


Option: 4

12


Answers (1)

best_answer

\mathrm{ \frac{\mathrm{I}_{\mathrm{s}}}{\mathrm{I}_{\mathrm{c}}}=0.96 \Rightarrow \mathrm{I}_{\mathrm{c}}=0.96 \mathrm{I}_{\mathrm{c}} }

But \mathrm{ \mathrm{I}_{\mathrm{c}}=\mathrm{L}_{\mathrm{c}}+\mathrm{I}_{\mathrm{b}}=0.96 \mathrm{~L}_{\mathrm{c}}+\mathrm{I}_{\mathrm{b}} \Rightarrow \mathrm{I}_{\mathrm{b}}=0.04 \mathrm{I}_{\mathrm{a}} }

\mathrm{ \therefore } \mathrm{ Current \; gain \beta=\frac{I_c}{I_b}=\frac{0.96 \mathrm{I}_c}{0.04 \mathrm{I}_{\mathrm{e}}}=24 }

Posted by

Riya

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

NTA Exams 2025 Live: NEET UG date, registration form soon at neet.nta.nic.in; UGC NET revised schedule out
anam-khan

Is it difficult to get into NIT Durgapur? JEE Main cut-offs for BTech programmes
anam-khan

JEE Main Deleted Syllabus 2025: Topics to skip this year; why no optional questions?

Latest Question