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  • In the circuit shown here, the point ‘C’ is  kept connected to point ‘A’ till the current flowing through the circuit becomes constant.  Afterward, suddenly, point

In the circuit shown here, the point ‘C’ is  kept connected to point ‘A’ till the current flowing through the circuit becomes constant.  Afterward, suddenly, point ‘C’ is disconnected from point ‘A’ and connected to point ‘B’ at time t=0. Ratio  of the voltage across resistance and the  inductor at t=L/R will be equal to :  

 

 

   

 

 

Option: 1

\frac{e}{1-e}


Option: 2

1


Option: 3

-1


Option: 4

\frac{1-e}{e}


Answers (1)

best_answer

 at t = 0

I = I_{o}. = \frac{E}{R}

After connecting point C to b current start decaying and at any time, t

 current becomes

I = I_{o} . e ^{- \frac{tR}{L}}

Voltage across resistor

V_{R} = IR = I_{o} R \:e ^{- \frac{tR}{L}}

at t= \frac{L}{R} , V_{R} = \frac{I_{o}R}{e}.

Voltage across inductor

V_{L} = - L \frac{dI}{dT} = - L (\frac{R I_{o}}{L}) . e ^{-1}

= - \frac{R I_{o}}{e} .

Ratio \frac{V_{R}}{V_{L}} = - 1

Posted by

avinash.dongre

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