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  • In the circuit shown in figure, the AC source gives a voltage V = 20 cos (2000 t). Neglecting source resistance, the voltmeter and ammeter readings will be (approximately):     &nb

In the circuit shown in figure, the AC source gives a voltage V = 20 cos (2000 t). Neglecting source resistance, the voltmeter and ammeter readings will be (approximately):
                                                                   

Option: 1

4V, 2.0 A


Option: 2

0 V, 2 A


Option: 3

5.6 V, 1.4 A


Option: 4

8 V, 2.0 A


Answers (1)

best_answer

\mathrm{\begin{aligned} & X_L=\omega L=(2000)\left(5 \times 10^{-3}\right)=10 \Omega \\ & X_C=\frac{1}{\omega C}=\frac{1}{(2000)\left(50 \times 10^{-6}\right)}=10 \Omega \end{aligned} }
\mathrm{Since, X_C=X_L \therefore \quad \mathrm{I}=\frac{\mathrm{V}}{\mathrm{Z}}=\frac{20 / \sqrt{2}}{10} or \ \mathrm{I}=1.4\mathrm{~A} \ and \mathrm\ {Voltmeter }= 1.4 \times\ 4 volt\ =\ 5.6\ V }

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shivangi.bhatnagar

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