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In the circuit shown in the figure, the ac source gives a voltage V = 20 cos (200 t). Neglecting source resistance, the voltmeter and ammeter reading will be:
                              

Option: 1

0 V, 0.47 A


Option: 2

1.68 V, 0.47 A


Option: 3

0 V, 1.4 A


Option: 4

5.6 V, 1.4 A


Answers (1)

\mathrm{\begin{aligned} & Z=\sqrt{(R)^2+\left(X_L-X_C\right)^2} \\ & R=10 \Omega X_L=\omega L=2000 \times 5 \times 10^{-3}=10 \Omega \\ & X_C=\frac{1}{\omega C}=\frac{1}{2000 \times 50 \times 10^{-6}}=10 \Omega \text { i.e., } Z=10 \Omega \end{aligned} }
\mathrm{ Maximum \, \, current, \mathrm{i}_0=\frac{\mathrm{V}_0}{\mathrm{Z}}=\frac{20}{10}=2 \mathrm{~A} }
\mathrm{ Hence, \mathrm{i}_{\mathrm{rms}}=\frac{2}{\sqrt{2}}=1.4 \mathrm{~A} and \mathrm{V}_{\mathrm{mms}}=4 \times 141=5.64 \mathrm{~V} }

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Sumit Saini

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