In the circuit shown in the figure the total charge is  750 \mu F and the voltage across capacitor C_2 is 20 V. Then the charge on the capacitor C_2 is.
       
Option: 1 450\; \mu C
Option: 2 590\; \mu C
Option: 3 160\; \mu C  
Option: 4 650\; \mu C

Answers (1)

\\ \text{Voltage across}\ C_{1}= V_{1}=\frac{q}{C_{1}}=\frac{\left(750 \times 10^{-6}\right)}{15 \times 10^{-6}}=50 \mathrm{V} \\ \text{Applied voltage,}\ V=V_{1}+V_{2}=50+20=70 \mathrm{V} \\ \text{Charge on}\ C_{3}=C_{3} V_{2}=\left(8 \times 10^{-6}\right) 20 =160 \times 10^{-6}=160 \mu \mathrm{C} \\ \therefore \ Charge \ on \ C_{2}=750-160=590 \mu \mathrm{C}

So option 2 is correct.

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