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  • In the Davisson-Germer experiment, electrons are scattered by a nickel crystal. If the distance between two adjacent planes in the nickel crystal is 2 nm, wavelength is 0.167nm, what is t

In the Davisson-Germer experiment, electrons are scattered by a nickel crystal. If the distance between two adjacent planes in the nickel crystal is 2 nm, wavelength is 0.167nm, what is the angle of diffraction for electrons diffracted at the third-order maximum?

Option: 1

38.5^{\circ}


Option: 2

50.0^{\circ}


Option: 3

28^{\circ}


Option: 4

73.1^{\circ}


Answers (1)

Using Bragg's law, we can calculate the angle of scattering for electrons diffracted at the third-order maximum as follows:

2 d \sin (\theta)=3 \lambda

where d is the distance between two adjacent planes in the nickel crystal, \lambda is the wavelength of the electrons, and \theta is the angle of diffraction. Rearranging the equation, we get:

\theta=\sin ^{-1}(3 \lambda / 2 d)

Given that \lambda=0.167 \mathrm{~nm} and d=2 nm, we get:

\theta=\sin ^{-1}(3 \times 0.617 / 4)=\sin ^{-1}(0.46)=28^{\circ}

Posted by

Sumit Saini

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