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In the estimation of bromine, 0.5 \mathrm{~g} of an organic compound gave 0.40 \mathrm{~g} of silver bromide. The percentage of bromine in the given compound is _____% (nearest integer) 

(Relative atomic masses of Ag nad Br are 108u and 80u, respectively).

Option: 1

34


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\quad 0.5 \mathrm{~g} of an organic compound gave 0.40 \mathrm{~g}$ of $\mathrm{AgBr}.

\mathrm{mole\: of \: B{r}= \text{mole of } \mathrm{AgBr}=\frac{0.4}{108+80}=\frac{0.4}{188}}

\Rightarrow \mathrm{mass ~of ~Br=\frac{0.4}{188} \times 80=0.17}

So, in 0.5 gram of an organic compound,0.17 gram of Br is present

% Br in compound =\frac{0.17}{0.5} \times 100 \%

                            \\ =34 \% \\

Answer is 34 (nearest integer)

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chirag

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