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  • In the following circuit the base current is <img alt="\mathrm{10 \mu \mathrm{A}}" src="h

In the following circuit the base current \mathrm{I_{B}} is \mathrm{10 \mu \mathrm{A}} and the collector current is 5.2 \mathrm{mA}. This transistor circuit Can be used as an amplifier? In the circuit \mathrm{R_{B}=5 \mathrm{~K} \Omega\, \, and \, R_{L}=1 \mathrm{~K} \Omega}.

Option: 1

Amplifier


Option: 2

Switch


Option: 3

 Both


Option: 4

None


Answers (1)

best_answer

We know that for a transistor in CE configuration to be used as an amplifier the BE junction must be forward biased & base collector junction must be reverse biased. In the given question we are required to just check this

loop -1

\mathrm{ I_{B} R_{B}-I_{C} R_{L}-V_{C B}=0}
\mathrm{ \Rightarrow V_{C B}=\left[\left(5 \times 10^{3} \times 10 \times 10^{-6}\right)-\left(5.2 \times 10^{-3} \times 10^{3}\right)\right] \mathrm{V}}
\mathrm{ =(0.05-5.2) \mathrm{V}}\quad \ldots(i)
\mathrm{ \Rightarrow \mathrm{v}_{\mathrm{C}}<\mathrm{v}_{\mathrm{B}}}

loop -2

\mathrm{ \mathrm{V}_{\mathrm{CE}}+\mathrm{I}_{\mathrm{C}} \mathrm{R}_{\mathrm{L}}-\mathrm{V}_{\mathrm{C}}=0}
\mathrm{\Rightarrow \mathrm{V}_{\mathrm{CE}}=(5.5-5.2) \mathrm{V}=0.3 \mathrm{~V} \Rightarrow \mathrm{V}_{\mathrm{C}}>\mathrm{V}_{\mathrm{E}}}
as emitter is grounded,
\mathrm{V_{C}=0.3 \mathrm{~V} \quad.... (ii)}

\mathrm{from\: (i) \: and\: \: (ii) \: \mathrm{V}_{\mathrm{B}}=5.5 \mathrm{~V}}
\mathrm{\Rightarrow } junction is forward biased & hence the given is transistor would not work as an amplifier.

Posted by

Gautam harsolia

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