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  • In the following nuclear reaction, <img alt="\mathrm{D \stackrel{\alpha}{\rightarrow} D_{1} \stackrel{\beta}{\rightarrow} D_{2} \stackrel{\alpha}{\rightarrow} D_{3} \stackrel{\gamma}{\rig

In the following nuclear reaction,

\mathrm{D \stackrel{\alpha}{\rightarrow} D_{1} \stackrel{\beta}{\rightarrow} D_{2} \stackrel{\alpha}{\rightarrow} D_{3} \stackrel{\gamma}{\rightarrow} D_{4}}

Mass number of D is 182 and atomic number is 74. Mass number and atomic number of \mathrm{D_{4}} respectively will be _____

Option: 1

\mathrm{174 \text { and } 71}


Option: 2

\mathrm{174 \text { and } 69}


Option: 3

\mathrm{172 \text { and } 69}


Option: 4

\mathrm{172 \text { and } 71}


Answers (1)

best_answer

\mathrm{\alpha }= \ \ ^{4}He_{2}

\mathrm{\bar{B} \rightarrow electron. }

\mathrm{D_{1}=^{182-4}D_{74-2}=^{178}D_{72}}

\mathrm{D_{2}=^{178}D_{73}} \\

\mathrm{D_{3}=^{174}D_{71}} \\

\mathrm{D_{4}=D_{3}=^{174}D_{71}}

Hence the correct option is 1.

Posted by

Rakesh

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