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In the network shown below, the charge accumulated in the capacitor in steady state will be :

Option: 1

4.8 \mu C


Option: 2

12\mu C


Option: 3

7.2\mu C


Option: 4

10.3\mu C


Answers (1)

best_answer

In steady state, no current will pass through capacitor hence capacitor will act as open circuit.i2 = 0
i_2=\frac{3}{6+4}=\frac{3}{10}A
Potential difference on 6\Omega resistor =6\times \frac{3}{10}=1.8  volt capacitor will have same potential so charge

=cv=4\times 1.8=7.2\mu C

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rishi.raj

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