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  • In Thomson's atomic model, an electron with a charge of <img alt="\mathrm{ -1.6 \times 10^{-19} C }" src="https://entrancecorner.oncodecogs.com/gif.latex?%5Cmathrm%7B%20-1.6%20%5Ctime

In Thomson's atomic model, an electron with a charge of \mathrm{ -1.6 \times 10^{-19} C }is moving with a speed of \mathrm{2.0 \times 10^6 m/s} in a region where the electric field is \mathrm{1.2 \times 10^6 N/C}. Calculate the magnitude and direction of the electric force experienced by the electron.

Option: 1

\mathrm{-192 \times 10^{-13} N}


Option: 2

\mathrm{-19.2 \times 10^{-13} N}


Option: 3

\mathrm{-1.92 \ N}


Option: 4

\mathrm{-1.92 \times 10^{-13} N}


Answers (1)

best_answer

The magnitude of the electric force experienced by the electron is given by:

\mathrm{F = qE}

Where F is the force, q is the charge of the electron, and E is the electric field.

Substituting the values, we get:

\mathrm{F = (-1.6 \times 10^{-19} C) \times (1.2 \times 10^6 N/C) = -1.92 \times 10^{-13} N}

The negative sign indicates that the force is in the opposite direction to the direction of the electric field.

Thomson's atomic model proposed that electrons in the atom were in motion and were negatively charged particles. In this question, we have to calculate the magnitude and direction of the electric force experienced by an electron moving in an electric field. The formula for the electric force is given by \mathrm{F = qE}, where F is the force, q is the charge of the particle, and E is the electric field. By substituting the given values, we can calculate the magnitude of the electric force experienced by the electron. The negative sign indicates that the force is opposite in direction to the electric field.

Posted by

Kuldeep Maurya

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