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  • In your laboratory, you trace the path of light rays through a glass slab for different values of angle incidence  and in each case measure th

In your laboratory, you trace the path of light rays through a glass slab for different values of angle incidence (\angle i) and in each case measure the values of the corresponding angle of refraction (\angle r) and angle of emergence (\angle e) On the basis of your observations your conclusion is : 

a) (\angle i) is more than (\angle r), but nearly to (\angle e)

b) (\angle i) is less than (\angle r), but nearly to (\angle e)

c) (\angle i) is more than (\angle e) , but nearly to (\angle r)

d) (\angle i) is less than (\angle e), but nearly to (\angle r)

 

 

 

 
 
 
 
 

Answers (1)

  Since light ray enters from a rarer (air) medium to a denser (glass) medium , so ray bends toward normal hence angle of incidence (angle between incident ray and normal) ∠i is more than angle of refraction (angle between refracted ray and normal ) ∠r .

  Now by Snell's law , when light ray goes into glass from air ,

                          μ=sini/sinr1?  ...................eq1 ,

                                 when light ray goes into air from glass ,

                           1/μ=sinr2?/sine 

but r1?=r2?  as they are corresponding angles ,

 therefore               1/μ=sinr1?/sine 

or                            μ=sine/sinr1?   ........................eq2 ,

by eq1 and eq2 , we get ,

                          sini/sinr1?=sine/sinr1? ,

or                       ∠i=∠e

Posted by

Satyajeet Kumar

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