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  • Iron oxide , crystallises in a cubic lattice with a unit cell edge length of <img alt="5.0 \AA" sr

Iron oxide \mathrm{FeO}, crystallises in a cubic lattice with a unit cell edge length of 5.0 \AA. If density of the \mathrm{FeO} in the crystal is 4.0 \mathrm{~g} \mathrm{~cm}^{-3}, then the number of \mathrm{FeO} units present per unit cell is  __________ (Nearest integer)
Given: Molar mass of \mathrm{Fe} and \mathrm{O} is 56 and 16 \mathrm{~g} \mathrm{~mol}^{-1} respectively. \mathrm{N}_{\mathrm{A}}=6.0 \times 10^{23} \mathrm{~mol}^{-1}

Option: 1

4


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

\begin{aligned} & \mathrm{d}=\frac{\mathrm{z} \times \mathrm{M}}{\mathrm{N}_0 \times \mathrm{a}^3} \\ & 4=\frac{\mathrm{z} \times 72}{6 \times 10^{23} \times 125 \times 10^{-24}} \\ & \mathrm{Z}=4.166 \cong 4 \end{aligned}

Posted by

vishal kumar

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