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\tan \left(\cos ^{-1} x\right) is equal to ?

Option: 1

\frac{\sqrt{1-x^2}}{x}\\


Option: 2

-\frac{\sqrt{1-x^2}}{x}\\


Option: 3

\frac{\sqrt{x^2-1}}{x}\\


Option: 4

\frac{\sqrt{1+x^2}}{x}\\


Answers (1)

best_answer

 

 

Graph of Principal Value of function f-1 (f (x)) (Part 2) -

Graph of Principal Value of function f-1 (f (x)) (Part 2)

  1. Graph of tan-1( tan (x))

The domain of the function is R and range is (- π/2, π/2)

            y = tan-1( tan (x))

∴          tan y = tan x

⇒         y = nπ + x, n ∈ I (integer)  

 

To draw the graph of y = tan-1( tan (x)), we draw all the line of y = nπ + x, n ∈ I for 

y∈(- π/2, π/2).

 


 

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\text{Assume }\cos^{-1}x=\theta \rightarrow \cos\theta=x\\ \tan (\cos ^{-1} x)=\tan \theta\\ =\frac{\sqrt{1-x^2}}{x}\\

Posted by

Divya Prakash Singh

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