Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  •   is the ratio of energies of photons produced due to transition of an electron of hydro

\mathrm{\frac{x}{x+4}}  is the ratio of energies of photons produced due to transition of an electron of hydrogen atom from its
(i) third permitted energy level to the second level and
(ii) the highest permitted energy level to the second permitted level.
The value of \mathrm{x} will be___________.

Option: 1

5


Option: 2

-


Option: 3

-


Option: 4

-


Answers (1)

best_answer

Let the energy in case (1) and case (2) be \mathrm{E_{1}\&E_{2}} respectively

\mathrm{\frac{E_{1}}{E_{2}}=\frac{x}{x+4}----(Given)}

\mathrm{E_{1}=-13.6\: eV\left [ \frac{1}{2^{2}}-\frac{1}{3^{2}} \right ]}\rightarrow (1)

\mathrm{E_2=-13.6 \mathrm{ev}\left[\frac{1}{2^2}-\frac{1}{n^2}\right]}

\mathrm{\frac{E_1}{E_2}=\frac{\left[\frac{1}{4}-\frac{1}{9}\right]}{\left[\frac{1}{4}-\frac{1}{n^2}\right]}=\frac{x}{x+4}}

\mathrm{n \rightarrow \infty }  (highest permitted level)

\mathrm{\frac{E_1}{E_2}=\frac{\frac{5}{3 6}}{\frac{1}{4}}=\frac{5}{9}=\frac{x}{x+4}}

\mathrm{x=5}

The value of x will be 5





 

Posted by

rishi.raj

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

JEE Main 2025: BTech ECE cut-offs for female candidates go up at top NITs
anam-khan

JEE Main 2025 Session 2 City Slip (OUT) Live: Admit card likely on March 29 at jeemain.nta.nic.in; cut-offs
anam-khan

AESL expands Aakash Digital 2.0 to offer AI-powered coaching for NEET, JEE, Olympiads

Latest Question