During an adiabatic compression, 830\, J of work is done on 2 moles of a diatomic ideal gas to reduce its volume by 50%.The change in its temperature (in K) is nearly:

Answers (1)

The work done in the adiabatic process is given as:

                                                \\W=\frac{n R \Delta T}{\gamma-1}$ \\ \\ or, $830=\frac{2 \times 8.3 \times \Delta T}{1.4-1}$ \\ \\ or, $\Delta T=20 K$

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