Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • Engineering
  • L-isomer of a compound <img alt="' \mathrm{A}^{\prime}\left(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{4}\right)" src="https://entrancecorner.oncodecogs.com/gif.latex?%27%20%5Cmathrm%7BA%7D%5E%7B%5C

L-isomer of a compound ' \mathrm{A}^{\prime}\left(\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{4}\right) gives a positive test with \left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]^{+}. Treatment 'A' with acetic anhydride yields triacetate derivative. Compound ' A' produces an optically active compound (B) and an optically inactive compound (C) on treatment with bromine water and \mathrm{HNO}_{3} respectively. Compound (A) is :

Option: 1


Option: 2


Option: 3


Option: 4


Answers (1)

best_answer

 

L- isomer(option 1 compound) gives positive test with \left.[\mathrm{Ag}(\mathrm{NH_{3}})]_{2}\right]^{+}due to presence of \mathrm{-CHO} group.


L- isomer(option 1 compound) Yield triacetate derivative with acetic anhydride; due to presence of 3\; \mathrm{-OH} group.

Hence, the correct answer is Option (1)

Posted by

qnaprep

View full answer

JEE Main high-scoring chapters and topics

Study 40% syllabus and score up to 100% marks in JEE

Similar Questions

Trending Articles/News

anam-khan

In JEE Main 2025 April 3 shift 2, chemistry takes U-turn to be tougher than physics, mathematics
anam-khan

JEE Main 2025 April 3 Exam Analysis 2025: Shift 1 paper easy to moderate; chemistry section ‘easiest’
anam-khan

JEE Mains 2025 admit card out for April 7, 8, 9 exams; download on jeemain.nta.nic.in

Latest Question